What is the Strength of the Magnetic Field in a Solenoid with Given Parameters?

AI Thread Summary
The discussion revolves around calculating the magnetic field strength in a solenoid with specific parameters: a length of 0.20 m, 1000 turns, and a current of 5.0 A. The formula used is B=μo*nI/l, leading to a calculated value of 3.14x10^-2T. However, the answer key suggests a value of 6.3x10^-3T, prompting confusion about the discrepancy. Participants consider the possibility that the answer key may be incorrect, as the calculations appear accurate. The thread highlights the importance of verifying calculations against established formulas in physics.
physgrl
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Homework Statement



A 0.20 m long solenoid contains 1000 turns and carries a current of 5.0 A. What is the strength of the magnetic field at the center of the solenoid if its radius is 10-2m?

a. 35.1*10-1T

b. 8.2*10-1T

c. .95*10-2T

*d. 6.3*10-3T

Homework Equations



B=μo*nI/l

The Attempt at a Solution



B=(4∏*10^-7)*1000*5A/.2m
B=3.14x10^-2T

the answer key says its 6.3x10^-3T...what am I doing wrong?
 
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physgrl said:

Homework Statement



A 0.20 m long solenoid contains 1000 turns and carries a current of 5.0 A. What is the strength of the magnetic field at the center of the solenoid if its radius is 10-2m?

a. 35.1*10-1T

b. 8.2*10-1T

c. .95*10-2T

*d. 6.3*10-3T

Homework Equations



B=μo*nI/l

The Attempt at a Solution



B=(4∏*10^-7)*1000*5A/.2m
B=3.14x10^-2T

the answer key says its 6.3x10^-3T...what am I doing wrong?

It could be that the answer key is wrong since your calculation looks fine.
 
Thanks!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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