What Is the Total Stretch When Two Springs Are Combined?

  • Thread starter Thread starter srebman
  • Start date Start date
  • Tags Tags
    Springs
AI Thread Summary
When two identical springs are combined in series to suspend a 1-kg block, each spring stretches by 10 cm due to the same force acting on them. Therefore, the total stretch of the combined springs is 20 cm. The spring constants remain the same for both springs since they are identical. Each spring experiences the same force, confirming the total stretch calculation. The discussion concludes that the total stretch for the double-length spring setup is indeed 20 cm.
srebman
Messages
2
Reaction score
0
I have a question on a recent assignment.

A weightless spring is stretched 10 cm by a suspended 1-kg block. If two such springs are used to suspend the block, one spring above the other, to effectively provide one double-length spring, then the total stretch of the double-length spring will be? Is the k constant the same in both cases?

Thank You,
Sean
 
Physics news on Phys.org
If two such springs
implies that the spring constants are the same.

Each spring experiences the same force since they are colinear.
 
If each spring experiences the same force, 1-kg, then each will have a 10 cm strech and total 20 cm combined?
 
srebman said:
If each spring experiences the same force, 1-kg, then each will have a 10 cm strech and total 20 cm combined?

Yes, that's correct.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Stretching of a rotating spring
Replies
8
Views
2K
Distribution of Energy when work is done on a system of 2 masses connected by a spring
Replies
17
Views
1K
Why can we move the spring with constant speed when we apply a force?
Replies
29
Views
2K
Energy stored in a double spring system
Replies
17
Views
1K
Stretched spring attached to the center of a pure rolling disk
Replies
11
Views
1K
Irodov- 1.123- Simple conceptual question with two masses connected by a spring
Replies
20
Views
570
Absolute motion analysis of pulley-spring system
Replies
10
Views
1K
Question about springs and rotational/translational energy
Replies
4
Views
1K
Finding effective spring constants
Replies
2
Views
4K
Time period of SHM & Energy conservation in pulley-spring-block system
Replies
24
Views
3K

Hot Threads

Recent Insights

Back
Top