What is the unknown charge if the net electrostatic force on particle 1 is zero?

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SUMMARY

The discussion centers on calculating the unknown charge (q) required for the net electrostatic force on particle 1 to be zero in a system of four particles arranged in a square. The known charges are q1 = q4 = 1.06 × 10-15 C, while q2 and q3 are the unknown charges. The net force acting on particle 1 by particle 4 is 8.45E-18 N, and the X component of the force from particle 2 is negative 6.00E-18 N. The correct calculation for q, after adjusting for the proper distance and charge sign, is determined to be negative 7.49E-16 C.

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Monkey_Man08
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1. The problem statement: In the figure four particles form a square with edge length a = 2.44 × 10-2 m. The charges are q1 = q4 = 1.06 × 10-15 C and q2 = q3 = q. What is q if the net electrostatic force on particle 1 is zero?
All variables and given/known data: The given variable are in the statement, but I have calculated and checked some other important variables.
  • Net force acting on particle 1 by particle 4 is 8.45E-18 N.
  • The X component of the force acting on particle 1 by particle 2 is negative 6.00E-18 N.
  • Distance from particle 1 to particle 4 is 0.034507 m.

Homework Equations

: Coulomb Force:
11bfec934e963740d4bed02c2062a4e7.png
, where k = 8.99E9[/B]

The Attempt at a Solution


Since I'm using the above equation to solve for q2, I used algebra to set it up as q2 = (F)(r2) / (k)(q1). Once I plugged the numbers I have (6.00E-18)(1.19E-3) / (8.99E9)(1.06E-15). Once I plug all that in the calculator, I'm left with 7.49E-16 C. But supposedly that is the wrong answer. I've checked my math enough to know all the information above "The attempt at a solution" portion is correct, so the problem must lie within this final step... I think.
 

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Note that when inputting my final answer I put in negative 7.49E-16 C, because in order for particle 2 and 3 to counteract the forces of particle 4, they must have a negative charge.
 
I was using the wrong distance for r in my final calculation. All is solved.
 

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