What is the vapor pressure of a solution containing glucose and water at 60.0C?

AI Thread Summary
To find the vapor pressure of a glucose-water solution at 60.0°C, the vapor pressure of pure water is given as 149.38 torr. The calculation involves using Raoult's Law, which requires the molar fraction of the solvent (water) in the solution. The molar fraction can be calculated using the formula nsolute/(nsolute + nsolvent), but it should be noted that the focus should be on the solvent's molar fraction. The discussion emphasizes the importance of correctly identifying the components in the calculation to achieve an accurate vapor pressure result.
beneakin
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Homework Statement


What is the capor pressure of a solution containing .15 mol of glucose (C6H12O6) and 1.65 mol of water at a temperature of 60.0C? the vapor pressure of pure water at this temperature is 149.38 torr


Homework Equations


Ralout's law?

P=PoX


The Attempt at a Solution


im guessing that the P on the left side of the eqn is is VP of pure water(149.38)

im not sure how to get x there is some formula like nsolute/(nsolute + nsolvent)


thanks
 
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You are on the right track.
 
how do i find X
 
Using formula like the one you have listed, just remember you are looking for molar fraction of solvent, not solute.
 
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