nesan
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Homework Statement
a fighter plane is moving in a horizontal circular path at a constant speed, it takes 9.8 seconds to change its heading by one quarter of a circle from north to east, if the radius of the curvature is 2.0 x 10^3, find
d) the velocity change
The Attempt at a Solution
v = d / t
d = square root ((2.0 x 10^3)^2 + (2.0 x 10^3)^2)
d ≈ 2828m
d / t = 288.6m/s
But the textbook says the answer is 4.5 x 10^2 m/s
I have no idea, in what other ways I can approach this. Help please. :( Pointing me in the right direction will do. ^_^ Thank you.