What is the velocity of electrons when released from 1 nm apart?

[accidentprone]

Homework Statement

Two electrons are held 1 nm apart and then released. Assuming them to be classical particles, how fast will they be moving when they are far apart?

Homework Equations

Not sure here really due to the lack of info give in the question. I know the work done would be qV and that this should be equal to the kinetic energy.

Also V = q / (4 (pi) (epsilon) (r)) where V is the electric potential caused by each electron and r is the distance between them.

The Attempt at a Solution

If I let r go to infinity this means V tends to 0. Hence the kinetic energy is 0 and so is the velocity. This seems a little simplistic however! Can anyone confirm my reasoning?

 

[Delphi51]

If I let r go to infinity this means V tends to 0. Hence the kinetic energy is 0 and so is the velocity.

Just a little accident in the last sentence!
The basic thing that is going on is that all the initial electrical energy is converted into kinetic energy when at a great distance (where, as you say, Ee is zero). So
Ee initial = Ek final
Put in your formulas and solve for v.

 

[accidentprone]

Thank you for the reply - I was so concerned about being told vaguely by the question that the electrons end up "far apart" that I completely ignored the 1 nm to begin with!