What is the voltage? AC circuit

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SUMMARY

The discussion focuses on calculating the voltage in an AC circuit with a 60 Hz power source and a peak voltage of 12.0 V. A participant incorrectly applied the formula v = V cos(2πft) to find the voltage 1.5 ms after a measured voltage of 10.0 V. The correct approach requires determining the time at which the voltage is 10.0 V in the waveform before adding 1.5 ms to that time to find the subsequent voltage. This highlights the importance of accurately identifying the reference point in AC voltage calculations.

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  • Knowledge of phase relationships in AC voltage
  • Proficiency in using time-domain equations for voltage calculations
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Electrical engineers, physics students, and anyone involved in AC circuit analysis will benefit from this discussion, particularly those working on voltage calculations and waveform interpretation.

Xaspire88
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A 60 Hz power source with a peak voltage of 12.0 V is connected to a resistor. At a particular instant the voltage across the resistor is 10.0 V and decreasing. What is the voltage 1.5ms later.

I tried using the equation

v= V cos(2 pi ft)

v= 12.0V cos(2pi (60Hz)(1.5 X 10^-3s))
v= 10.13 volts.. but this is incorrect. Help please
 
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:rolleyes:Please help me out. Thank you.
 
If you are taking the instant of 12V to be your t=0, you have to first figure out at what time the 10V occurs in the waveform. Then add the 1.5 ms onto that number to find the voltage at 1.5 ms after the 10V. Does that make sense? What you have found is the voltage at 1.5 ms after your max voltage of 12V, which is not what the question is asking.
 

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