What Is the Voltage Between Points a and b?

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Homework Help Overview

The discussion revolves around determining the voltage between two points, labeled a and b, in a circuit involving resistors in series and parallel configurations. The context includes the application of Ohm's Law and the analysis of voltage drops across specific components.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the configuration of resistors and the calculation of equivalent resistance. Questions arise regarding the correct method to find the voltage between points a and b, particularly focusing on the total current and voltage drops across specific resistors.

Discussion Status

Some participants have offered guidance on considering the total current from the battery and the voltage drop across the 2.5Ω resistor. There is an ongoing exploration of how to accurately determine the voltage drop between the specified points, with some calculations presented for review.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information available for the problem. There is also a focus on ensuring the correct interpretation of circuit elements and their connections.

Eman 5

Homework Statement


I want to know the voltage between a and b in the drawing below.[/B]
i1lnD.jpg


Homework Equations


V= IR

The Attempt at a Solution


The resistors 5Ω and 5Ω are in series:
(Req)1= 5+5=10Ω
The resistors (Req)1, 5Ω and 10Ω are in parallel:
1/(Req)2= 1/10+1/5+1/10=2/5
(Req)2=2.5Ω
The resistors (Req)2 and 2.5Ω are in series:
Rt=2.5+2.5=5Ω
I=V/Rt=15/5=3A
The voltage between a and b= IR
I have I but I don't know how to get R between the two points.
 

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Edited: Start by finding the total current put out by the battery. Then consider the voltage drop across the 2.5 Ω resistor.
 
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@Eman 5
You should know that iR, in this case, is the voltage drop between any branch in the circuit you drew, i.e. you can consider any branch of them to determine the voltage drop (potential difference) between the points a and b, because all branches in this circuit are connected to the points a and b.

For example, consider the above branch which has the battery and the 2.5 ohms resistance. Remember that the current passing through that branch is 3A.

Now determine the potential difference through that branch.
 
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The voltage across 2.5Ω resistor=IR=3×2.5=7.5V
The voltage drop across the above branch= 15−7.5=7.5V
Is this correct?
 
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Eman 5 said:
The voltage across 2.5Ω resistor=IR=3×2.5=7.5V
The voltage drop across the above branch= 15−7.5=7.5V
Is this correct?
Yes.
 
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