- #1
hytuoc
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Plz help ASAP!
Iron has a mass of 7.87g/cm^3 of volume, and the mass of an iron atom is 9.27x10^(-26)kg. If the atoms are spherical and tightly packed,
a) a) what is the volume of an iron atom? --> this one I do know how to do it, the answer is 1.18x10^29 m^3
b) what is the distance between the centers of adjacent atoms?
This one, my answer is different than the answer in the book
This was how I did it:
b) [(1.18 x 10^29 m^3) x 3/4] / pi = r^3
r= 3.04 x 10^9 m
=> the distance between the centers of adjacen atoms is 6.08 x 10^9 meters
****but the answer of the book is 0.282 nm
Would someone please show me how to do part b of the problem? Thanks so much
Iron has a mass of 7.87g/cm^3 of volume, and the mass of an iron atom is 9.27x10^(-26)kg. If the atoms are spherical and tightly packed,
a) a) what is the volume of an iron atom? --> this one I do know how to do it, the answer is 1.18x10^29 m^3
b) what is the distance between the centers of adjacent atoms?
This one, my answer is different than the answer in the book
This was how I did it:
b) [(1.18 x 10^29 m^3) x 3/4] / pi = r^3
r= 3.04 x 10^9 m
=> the distance between the centers of adjacen atoms is 6.08 x 10^9 meters
****but the answer of the book is 0.282 nm
Would someone please show me how to do part b of the problem? Thanks so much