What is the Vrms, in m/s, for helium atoms at 4.8 K?

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The discussion focuses on calculating the root mean square velocity (Vrms) of helium atoms at a temperature of 4.8 K. The formula used is Vrms = √(3RT/M), where R is the ideal gas constant and M is the molar mass of helium. Participants clarify that the correct value of R must be used in SI units and confirm that the temperature should be 4.8 K, not 4.15 K. The molar mass of helium is correctly identified as 0.004003 kg. The conversation emphasizes the importance of using accurate constants for the calculation.
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Homework Statement


What is the Vrms, in meters per second, for helium atoms at 4.8 K? (which is close to the point of liquefaction)

Homework Equations


Vrms= √(3RT)/(M)

The Attempt at a Solution


R=3.145
T= I think its 4.15 Kelvin? based on the point of liquefaction of helium being -269°C
-unsure about the temperature
M= I think its 0.004003 Kg based on the molar mass of helium

Vrms= Sqrt (3*3.1845*4.15)/(0.004003)

Any help would be greatly appreciated, I've tried this a million ways and can't seem to figure it out,
Thank You!
 
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Welcome to PF!

You don't have the correct value of R if you are using SI units.

They want you to use 4.8 K for T.

Otherwise, your method looks correct.:smile:
 
TSny said:
Welcome to PF!

You don't have the correct value of R if you are using SI units.

They want you to use 4.8 K for T.

Otherwise, your method looks correct.:smile:

Thank You!
 
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