What is the weight of a hollow sphere underwater?

AI Thread Summary
To determine the weight of a hollow sphere underwater, first convert its mass and density to SI units, resulting in a density of 3000 kg/m³ and a mass of 0.12 kg. The weight of the sphere in air is calculated using the formula w=mg, leading to a downward force. To find the weight underwater, calculate the buoyant force, which equals the weight of the water displaced by the sphere. The final weight of the sphere underwater is 0.8 N after accounting for buoyancy. Understanding these principles is essential for solving similar physics problems.
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Homework Statement



A hollow sphere has average density of 3 g/cm^3 and a mass of 120g. What will the sphere weight under water?

correct answer: 0.8

Homework Equations



d=m/v

w=mg


The Attempt at a Solution



I converted 120g into kg and then used w=mg to find weight on land. however, this does get 0.8N underwater. Please help thanks!
 
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first, change all the units to SI units, giving you:
3000 kg/m3 for the sphere's density
0.12 kg for its mass

to possibly calculate the sphere's weight underwater, you must calculate the net force of the sphere's weight downwards and buoyancy upwards

buoyant force is equal to the weight of the water displaced by the ball, thus you calculate the weight by using the mass of the water displaced, found by:
1. density of water
2. the volume of water displaced, which is equal to the volume of the sphere since it is fully submerged
 
got it, thanks!
 
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