What is the Work Done by a Heated Metal Rod?

AI Thread Summary
The discussion revolves around calculating the work done by a heated metal rod based on its physical properties, including length, cross-sectional area, Young's modulus, and coefficient of linear expansion. The formula derived for work done is 1/2 YAL(α∆t)², which is compared to a book's answer of 1/2 YAL(αt)². The discrepancy arises from the assumption of a reference temperature, with the book likely using zero degrees Celsius. Participants note that the problem statement does not specify a reference temperature, leading to confusion. Ultimately, both answers appear to be correct under different assumptions regarding the initial temperature.
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Homework Statement


a metal rod of length "L",cross sectional area "A",young modulus "Y" and coefficient of linear expansion "α " is heated to "t" degree celsius .The work that can be performed by the rod when heated is

Homework Equations


work done by rod when heated=1/2 force exerted by rod(when heated) multiplied by extension
I know force exerted by rod(when heated)=Y α ∆t multiplied by A
(here ∆t is increase in temperature by due to heating)and extension would be final length -initial length let L' be final length.So extension would be L' - L
As L'=L(1 +α ∆t )
So L' - L=Lα ∆t

The Attempt at a Solution


with the help of equations above we can see
work done by rod when heated=1/2 Y α ∆t A multiplied by Lα ∆t
=1/2 YAL(α ∆t )^2
right?but in my book answer is given 1/2 YAL(αt)^2
which one is right?
 
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It looks like the reference for the exercise writer is zero degrees celsius. You take a more general approach where the environment temperature can be 0 or 20 or whatever.
Apart from that I see no difference between your answer and the book answer ..

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Last edited:
BvU said:
It looks like the reference for the exercise writer is zero degrees celsius.
if that's the case then
BvU said:
no difference between your answer and the book answer ..
but as we can see nothing such is mentioned in the question
 
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