What Is the Work Required to Accelerate a Proton from 0.5c to 0.7c?

AI Thread Summary
To calculate the work required to accelerate a proton from 0.5c to 0.7c, the work-energy theorem must account for relativistic effects. The incorrect method used was the classical kinetic energy formula, which is not valid at high speeds. The correct approach involves using the relativistic kinetic energy equation: KE = mc^2((1/sqrt(1-(v^2/c^2)))-1). This formula yields the correct work value, which is approximately 3.69e-11. Understanding and applying relativistic principles is crucial for accurate calculations in high-energy physics.
SsUeSbIaEs
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Can some one help me out here, I have tried using several different methods but I still don't know what I am doing wrong.

The question is:

A proton in a high energy accelerator moves w/a speed of 0.5c, use the work-energy theorem to find the work required to increase its speed to 0.7c.


I have tried /\K=.5m(vf^2-vi^2), what am I doing wrong?
 
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You're not taking into account relativistic effects.

cookiemonster
 
Ugh!?

I don't know what your talking about,

I thought I would use:

.5m( (.7*c)^2-(.5*c)^2)

c= the speed of light

I was also told an equation like m^2c^2((1/sqrt(1-(v^2/c^2)))-1), but I kept geting zero for my answer and the actual answer is like 3.69??e-11, but I do not know how they got this answer??
 


Originally posted by SsUeSbIaEs
.5m( (.7*c)^2-(.5*c)^2)
This is only correct for low, non-relativistic speeds.
I was also told an equation like m^2c^2((1/sqrt(1-(v^2/c^2)))-1) ...
Use the relativistically correct expression for KE:
KE = mc^2((1/sqrt(1-(v^2/c^2)))-1)
 
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