What is voltage when running current through copper plats?

AI Thread Summary
The discussion revolves around calculating the voltage when running current through copper plates, specifically bitter disks, in a solenoid setup. Using Ohm's Law and the resistivity of copper, the calculated voltage is approximately 0.00001524 volts with a current of 0.086 amps and a resistance of 0.0001772 ohms. Participants inquire whether overlapping copper plates would increase resistance and subsequently affect voltage, as well as the impact of insulation between the plates on resistance. The calculations and questions highlight the complexities of electrical resistance in practical applications involving copper materials. Understanding these factors is crucial for optimizing solenoid design and performance.
Matt01
Hey everyone, I'm hoping that you guys will be able to help me with some calculations. I was on YouTube and came across this:


I then began to wonder if I could make a solenoid using bitter disk as in the video, granted no where near as powerful. I would say 1 tesla using an iron core. After some digging, I found the bitter disk are .27 mm thick or thicker and as the video says made of a copper silver alloy. To simplify let's use pure copper. Since current generates heat, and as heat increases, so do the resistance of the copper, let's say the copper disks are being called by water or some other cooling mechanism to keep them at room temps.

Known:

B=unl
length is 12inches/.3048m
r = 1 inch
bitter disk would need to be big enough for the iron to go through and extend 2 inches out from the inner edge.
turns = 564.4
There would be 564.4 insulators
turn density is n=N/L = 1850 turns/m
I = 0.086 amps
B = 1 tesal
u = relative permeability = Iron (99.8% pure) 6.3 10−3 5000
source: https://www.engineeringtoolbox.com/permeability-d_1923.html

Ohm's Law : V = IR
V = volts
I = current in amps
R = resistance
R = ρL/A = Resistance of the wire(bitter disk)
P = Resistivity of copper ρ = 1.7 x 10-8 Ωm
L = is the length
A = The area is the cross-sectional area of the wire

Unknown:

My best guess for the cross-sectional area of the bitter disk would be: a = L*w
a = 50.8 mm * .27 mm = 8.636 mm ^2 = 0.008636 m^2
My best guess for the length the current would travel would be to take the circumference of a circle or in this case the bitter disk * number of turns and convert to meters.
c = 2 π r = 2 * π * 25.4mm = 159.593 mm = 0.159593m * 564 = 90.01m
(1.7 x 10-8 Ωm * 90.01m)/ (0.008636 m^2)
R = 0.0001771850393700787Ω
V = IR
V = 0.086 amps * 0.0001771850393700787Ω = 0.0000152379133858267682 volts
V = 0.00001524 volts

Questions:

What would the voltage be?
Would the overlapping copper plates add more resistance and increase the voltage?
Would the insulation between the copper plates add resistance?
 
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