What mass would be required to overcome static friction?

Click For Summary
SUMMARY

The discussion centers on calculating the mass required to overcome static friction for a block of wood weighing 1.53 x 103 g on a wood table, with a coefficient of static friction of 0.40. The correct approach involves using the equation where the frictional force equals the coefficient of static friction multiplied by the mass of the block. Specifically, the equation is 1.53 x 103 g * 0.40 < mg, where 'm' represents the mass needed to overcome the frictional force.

PREREQUISITES
  • Understanding of static friction and its coefficient
  • Basic knowledge of Newton's laws of motion
  • Familiarity with force and mass calculations
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the concept of static friction and its applications in physics
  • Learn how to calculate forces using Newton's second law
  • Explore pulley systems and their mechanics
  • Practice solving problems involving frictional forces and mass
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of static friction calculations.

Amber3046
Messages
6
Reaction score
0

Homework Statement


The coefficient of static friction for wood on wood is 0.40, what mass would be required to overcome static friction of a 1.53 x 10^3 g block of wood on a wood table?


Homework Equations


I have absolutely no idea.


The Attempt at a Solution


I don't know.
Thanks for your help.
 
Physics news on Phys.org
Amber3046 said:

Homework Statement


The coefficient of static friction for wood on wood is 0.40, what mass would be required to overcome static friction of a 1.53 x 10^3 g block of wood on a wood table?


Homework Equations


I have absolutely no idea.


The Attempt at a Solution


I don't know.
Thanks for your help.
Perhaps the problem is that you are asking the wrong question. Mass will not "overcome friction". I presume you mean "force". Well, the definition of "coefficient of static friction" is "force required to move divided by mass" so the force you want is the coefficient of static friction multiplied by the mass.
 
Are you talking about a system where a block of wood is on a table and it is attached to a mass (through a pulley) which is hanging over the table? Because if so, what's needed is the mass which satisfies this equation:

1.53*10^3g * .4 < mg
(Friction Force) (Weight of mass)

p.s. I assume the g you used was grams?
 

Similar threads

Replies
16
Views
3K
Replies
4
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
6
Views
3K
Replies
22
Views
2K
Replies
61
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K