# What mass would be required to overcome static friction?

1. Mar 5, 2009

### Amber3046

1. The problem statement, all variables and given/known data
The coefficient of static friction for wood on wood is 0.40, what mass would be required to overcome static friction of a 1.53 x 10^3 g block of wood on a wood table?

2. Relevant equations
I have absolutely no idea.

3. The attempt at a solution
I don't know.

2. Mar 5, 2009

### HallsofIvy

Perhaps the problem is that you are asking the wrong question. Mass will not "overcome friction". I presume you mean "force". Well, the definition of "coefficient of static friction" is "force required to move divided by mass" so the force you want is the coefficient of static friction multiplied by the mass.

3. Mar 5, 2009

### thepopasmurf

Are you talking about a system where a block of wood is on a table and it is attached to a mass (through a pulley) which is hanging over the table? Because if so, what's needed is the mass which satisfies this equation:

1.53*10^3g * .4 < mg
(Friction Force) (Weight of mass)

p.s. I assume the g you used was grams?