What Was the Energy of the Incoming Photon?

jacksonb62
Messages
21
Reaction score
0
1.
An elementary particle of mass M completely absorbs a photon, after which its mass is 1.01M. (a) What was the energy of the incoming photon? (b) Why is that energy greater than 0.01Mc2?




Homework Equations


p (photon) = E/c
p (particle) = γmv
p(i) = p(f)
Ek = γmc^2 -mc^2

The Attempt at a Solution


I really have no idea where to start without having knowledge of the velocity of the particle after the collision
 
Physics news on Phys.org
Just use v as velocity. Momentum conservation will give you that velocity during the calculations.
 
jacksonb62 said:

Homework Statement



An elementary particle of mass M completely absorbs a photon, after which its mass is 1.01M. (a) What was the energy of the incoming photon? (b) Why is that energy greater than 0.01Mc2?


Homework Equations


p (photon) = E/c
p (particle) = γmv
p(i) = p(f)
Ek = γmc^2 -mc^2


The Attempt at a Solution


I really have no idea where to start without having knowledge of the velocity of the particle after the collision
Was that the complete problem statement? I don't think the situation described is physically possible.
 
It is possible, it is the reverse process of a gamma decay.
 
But that's with a nucleus, which has a substructure. I guess it seems a little odd to me to say that an elementary particle changes its mass by absorbing a photon unless it's referring to its relativistic mass.
 
It becomes a different elementary particle. There are no suitable elementary particles for that process (and it would probably need weak higher-order processes), but I don't think we have to worry about that.
"Mass" has to be rest mass, otherwise the second question does not make sense.
Elementary just guarantees we don't have to worry about rotations and so on.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top