What was the force exerted on the bullet bringing it to rest?

AI Thread Summary
To determine the force exerted on a bullet that comes to rest after penetrating a tree, the initial speed of the bullet is 350 m/s, its mass is 3 grams (0.003 kg), and it penetrates 12 cm (0.12 m). The discussion emphasizes the relationship between the work done by the stopping force and the bullet's initial kinetic energy. Participants are encouraged to show their calculations to receive assistance. The problem requires applying physics equations related to force and energy. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


a 3 gram bullet traveling at 350m/s squared hits a tree and slows down uniformly to a stop while penetrating a distance of 12 cm into the tree's trunk. What was the force exerted on the bullet bringing it to rest?


Homework Equations





The Attempt at a Solution

I know the speed is 350m/s , the weight is .003 kg, and the distance it traveled is .12 m. I can't figure out how to get the Newtons so i can get the joules. I am stuck.
 
Last edited:
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Welcome to the forums. Please note that for homework questions we need to see your working before we can help you. Do you have any thoughts? Hint: how does the work done by the force stopping the bullet relate to the total energy of the bullet before it hits the tree?
 

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