What would be my boundary conditions? Heat Equation

punkstart
Messages
4
Reaction score
0
1. I have a rod of length 4,cross section 1 and thermal conductivity 1.Nothing is mentioned about the end at the origin x=0, but at the opposite end x=4, the rod is radiating heat energy at twice the difference between the temperature of that end and the air temperature of 23 celcius. Find the boundary conditions at this x=4 end of the rod to be used in the one dimensional heat equation.



2. Heat flows out of rod at -\lambda A u_{x}(a,t)




3. with my substitutions i get -u_{x}(4,t)=2(u(4,t)-23)
So that my first boundary condition is the above. But i think " they " want another boundary condition here at x=4,but what ? I was thinking something like u(4,t)=u(4,0)-tu_{t}(4,t) in other words temperature now = initial temperature - time*rate of temperature loss. i am not very experienced with these problems,can someone please point me in the right direction ?
 
Physics news on Phys.org
so based on the boundary condition the you can calculate the heat moving out teh end of the rod
Q = 2(u(4,t) - 23))

Assuming the heat flow is reasonably continuous which is a good assumption you should be able to relate the heat flow to the thermal gradient at the end of the rod u_x(4,t), using the thermal conductivity
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top