- #1
yuze
- 3
- 0
When I have:
y''-yu^2=0
Why can't I just solve it using y=Ae^ux+Be^-ux ?
Is there any specific reason for me to use y=Acoshx + Bsinhx?
Also, for questions such as ut=uxx-u with BC u(0,t)=0 and u(L,t)=u1
When I am setting up u=v+w do I have to set V as Acoshx+Bsinhx?
I saw the solutions do that, but why can't I set V as u1x/L in this case?
y''-yu^2=0
Why can't I just solve it using y=Ae^ux+Be^-ux ?
Is there any specific reason for me to use y=Acoshx + Bsinhx?
Also, for questions such as ut=uxx-u with BC u(0,t)=0 and u(L,t)=u1
When I am setting up u=v+w do I have to set V as Acoshx+Bsinhx?
I saw the solutions do that, but why can't I set V as u1x/L in this case?