When Does the Angular Velocity of a DC Motor Reach Zero?

Click For Summary

Homework Help Overview

The problem involves a DC electric motor where the current is reversed at time t=0, leading to an angular displacement described by a cubic function of time. The main question is to determine when the angular velocity of the motor shaft becomes zero.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss taking the derivative of the angular displacement function to find the angular velocity. There is confusion regarding the application of the quadratic formula and the physical meaning of the resulting times. Some participants also explore how to calculate the number of revolutions the motor shaft completes before the angular velocity reaches zero.

Discussion Status

Some participants have made progress in understanding the problem, while others are still clarifying their approach to finding the time when angular velocity is zero. Guidance has been offered regarding the conversion from radians to revolutions, but there is no explicit consensus on the correct method or interpretation of the results.

Contextual Notes

Participants are navigating through the implications of reversing current and the resulting motion of the motor, with some expressing uncertainty about the physical significance of their calculations. There is mention of potential confusion regarding the coefficients in the angular displacement equation.

nateshoe
Messages
9
Reaction score
0

Homework Statement



At t=0 the current to a dc electric motor is reversed, resulting in an angular displacement of the motor shaft given by theta (t) = ( A)t-( B)t^{2}-( C)t^{3}

At what time is the angular velocity of the motor shaft zero?

Homework Equations



quadratic

The Attempt at a Solution



I continue to be very confused by this question. I thought all I need to do was take the derivative with respect to time and then plug those coefficients into the quadratic equation.
So I get:

(2B(+/-)((4B^2+12AC)^.5))/2A
 
Physics news on Phys.org
1. You have interchanged the roles of A and -3C here, so your expression is not correct.
2. Which of the times you get out is not physically meaningful?
 
Well I got that part figured out but I can't get the next part.

1.
How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero?
2.
Deltatheta=.5(w+w0)t
revolution=(1/2pi)radians
3.
Since the final velocity is zero:
deltatheta=.5tw0
revolutions=(.5tw0)/(2pi)
w0=A
so;

=.5tA/2pi (where t is the time when angular velocity =0)


Thanks,
Nate
 
Question: How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero?

Ans: Well, assuming that you found the time t when the angular velocity is zero, all you need to find out here is the revolutions between zero and that time t.

Plug in the time t into the angular displacement equation that you have, and you should get something in radian measure.

Then, the next thing that tricked me out was that I didn't know the conversion from radian to revolutions. (a simple thing, I know, but I overlooked it)

1 revolution = 2*pi radians.

Convert, and viola you have how many revolutions.
 

Similar threads

Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
4
Views
14K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
3
Views
896