When is y = 2/(4-x) concave downwards?

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17. For what value of x is the graph of y = 2 / (4 - x) concave downwards?

I found the first derivative = 2/(4-x)^2

And then the second 4/(4-x)^3

But I think I might have messed up somewhere in there
 
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You're not doing the derivatives correctly. You need to use this rule:

http://archives.math.utk.edu/visual.calculus/2/quotient_rule.4/index.html

\left( \frac{f}{g} \right)' = \frac {gf' - fg'}{(g)^2}
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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