A graph in polar coordinates is given by r=f(\theta).
Now, we can express such a graph in cartesian coordinates. So, if r=f(\theta), then we can use the formulas
x=r\cos(\theta),~y=r\sin(\theta)
to come up with the following form of the graph in cartesian coordinates:
(f(\theta)\cos(\theta),f(\theta)\sin(\theta)
For example, given r=a-\cos(\theta) (with a constant), we can write this in cartesian coordinates as
((a-\cos(\theta))\cos(\theta),(a-\cos(\theta))\sin(\theta))
Now, the use of this is simpy that we can now investigate our curve using analysis. So, we can find the "velocity vector" at a point by taking derivatives. The derivative of our above function now becomes
(\sin(\theta)(2\cos(\theta)-a),a\cos(\theta)-\cos(2\theta))
Now, if a=3/2, then our derivative in 0 is (0,1/2)
So, we can deduce that in 0, our function is going up with a speed of 1/2.
What if a=1? Then our derivative in 0 is (0,0). This is a weird result. It means that at 0, our velocity vector is zero and thus the curve just stands still. This is the explanation of why you get a sharp point (= a cusp) when a=0, but just a smooth line when a=3/2.
