I have attached the known information.
When the truck is at rest, will the crate also be at rest or will it slide
Sum F_y =0
G_max = (my_s)*N
G_min = (my_k) * N
The Attempt at a Solution
I did a Free body diagram on the crate (see the attached file)
The first step is finding the normal force.
Sum F_y =m*a_y =0
now i find the friction forces
G_ max=(my_s)*N= 0.70*1932.19=1352.53 N
Now i will find F_II
F_II = m*g*sin(10) = 340.70 N
since G_max > F_II there is no motion downwards i,e a_x = 0
I am not sure if I have done it correct.
Thank you for your help.
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