When to Use Ln vs Log in Calculating Derivatives?

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Homework Help Overview

The discussion revolves around the differentiation between the use of natural logarithm (ln) and common logarithm (log) in calculus, particularly in the context of evaluating derivatives. The original poster expresses confusion regarding when to use each notation while attempting to differentiate a function.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the conventions surrounding the use of ln and log, questioning the general rules for their application in derivatives. There are discussions about the notation differences in various texts and contexts, as well as the implications of using one over the other.

Discussion Status

Some participants have provided clarifications regarding the derivatives of ln and log, noting that ln(u) is the derivative of 1/u. There is an ongoing exploration of the notational conventions and their implications in different mathematical contexts, with no explicit consensus reached on the best practice.

Contextual Notes

There is mention of varying conventions in textbooks and computer algebra systems regarding the use of log and ln, which may lead to confusion. Additionally, the importance of specifying the base in logarithmic functions is highlighted, especially in different fields of study.

Drake M
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Homework Statement


I'm having a hard time differentiating when to use log instead of ln, vice versa. Are there any general rules to follow?

For example I have to evaluate 4u^-3 + u^-1.

Homework Equations


f'(1/u) = log u
f'(1/u) = ln u

The Attempt at a Solution


I put -2u^-2 + log(u) but the textbook solution shows the same answer except with ln.
 
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The derivative of 1/u is ln(u), not log10(u). When you are dealing with derivatives or integrals, the natural log has an advantage. In those situations, log10 requires that you correctly include factors of ln(10) in your answers.
CORRECTION: The derivative of ln(u) is 1/u. ( Thanks @lcgldr)
 
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Drake M said:

Homework Statement


I'm having a hard time differentiating when to use log instead of ln, vice versa. Are there any general rules to follow?

For example I have to evaluate 4u^-3 + u^-1.

Homework Equations


f'(1/u) = log u
f'(1/u) = ln u

The Attempt at a Solution


I put -2u^-2 + log(u) but the textbook solution shows the same answer except with ln.

Some books and papers denote the natural logarithm of ##u## as ##\log(u)## instead of ##\ln(u)##. Some other books reserve the notation ##\log(u)## for log to base 10 of ##u##. Still others use ##\log_{10}(u)## instead in that context.

I do believe that the most common forms are ##\ln(u)## for ##\log_e(u)## and ##\log(u)## for ##\log_{10}(u)##, but I have no statistics on that issue.

Some computer algebra systems adopt similar standards. For example, Maple accepts either "log(u)" or "ln(u)" for ##\ln(u)## but prints it out as ##\ln(u)##. It needs the fancier notation "log[a](u)" for ##\log_a(u)## when ##a \neq e##. I don't have access to Mathematica, so I don't know what conventions it adopts.
 
Just for clarity, I recommend the use of ln() for base e and loga() for arbitrary base a. Otherwise, it leaves people guessing what base you want. It's nicer to specify the base when you use 'log'.

The exception is in math books like complex analysis, where the base is always e, regardless of the 'ln', versus 'log' choice.
 
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I think the notation ##\ln u## is common in applied, less rigorous mathematics, especially senior high school level math. Pure mathematics literature usually assumes that ##\log u## means the base ##e## logarithm unless otherwise stated. The base-10 logarithm is important in chemistry, where the pH scale is defined with it.
 
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I meant to thank you all for your help sooner but i got caught up in test and mid-terms. Thanks!
 

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