When we can say that a waveguide is perfectly matched?

AI Thread Summary
A waveguide is considered perfectly matched when there is no reflected power at its termination interface. Achieving a perfect match is nearly impossible, leading to some level of reflected signal in practice. To manage reflected power in RF transmission lines, devices like circulators are used to redirect it to a dummy load instead of allowing it to return to the transmitter. This prevents potential issues such as intermodulation products. For further clarification, more specific questions can be posed.
vinusherkhane
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please explain somebody what it means I am totally confused.
 
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Hi there
welcome to PF :smile:

its perfectly matched where there is no reflected power from the interface of whatever the waveguide is terminating into
this goes for any transmission line
of course a perfect match would be near impossible to obtain and we would always have to put up with some reflected signal
which is why in RF transmission lines, coax or waveguides, we use circulators to terminate reflected power into a dummy load, rather than letting it go back into the transmitter where it will produce all sorts of nasty intermodulation products

if you need a better explanation than that, then maybe ask a more specific question :wink:

cheers
Dave
 
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