Calculating Magnetic Field of a Solenoid: Where Did I Go Wrong?

  • Thread starter lw11011
  • Start date
In summary, the conversation discussed the process of finding the magnetic field along the axis at the center of a solenoid given its length, turns, radius, and current using the formula B = \frac{\mu_0.I.N}{l}. The output should be in units of T and it was noted that the answer may have been incorrect if the computer program for homework marked it as such.
  • #1
lw11011
8
0
A solenoid 77.1 cm long has 340 turns and a radius of 1.92 cm. If it carries a current of 1.85 A, find the magnetic field along the axis at its center. Answer in units of T.
I know the formula for the magnetic field is:
Magnetic field = permeability x turn density x current
I entered -
B=(1.25664x10^-6)(340/.771)(1.85)
Where did I go wrong?
 
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  • #2
Magnetic field = permeability x turn density x current

I think you could use this

[tex]B = \frac{\mu_0.I.N}{l}[/tex]
 
Last edited:
  • #3
ranger said:
I think you could use this

[tex]B = \frac{\mu_0.I.N}{l}[/tex]

:tongue2: He DID use that formula. You just reproduced what he said in words using symbols.
 
  • #4
lw11011 said:
Where did I go wrong?

Looks ok so far. What makes you think that you went wrong? You didn't even post an answer, so it is not at all clear from your post what the problem is.
 
  • #5
cepheid said:
:tongue2: He DID use that formula. You just reproduced what he said in words using symbols.

:biggrin: I stand corrected :approve:
 
  • #6
By using that formula I got the answer, 0.001 T. The computer program for our homework said the answer was wrong.
 

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