Where Does a Cut String Leave a Moving Mass After 4 Seconds?

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When the string is cut, the mass continues to move with its initial velocity of -3 m/s in the x-direction and 2 m/s in the y-direction. Since there are no external forces acting on the mass after the string is cut, its velocity remains constant. Over a period of 4 seconds, the mass will travel a distance calculated by multiplying its velocity by time, resulting in a displacement of -12 m in the x-direction and 8 m in the y-direction. Therefore, the new position of the mass after 4 seconds will be at (-12, 8) relative to its original position. The effects of gravity and friction are ignored in this scenario.
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A weight with a mass of 3 kg is attached to a string of length 50 cm. One end of the string is fixed at the origin (x=0, y =0) and the weight is pushed on a frictionless table top so that it moves horizontally in a circle with constant angular velocity %omega. The weight moves in the x-y plane, z=0. At a certain time the velocity of the mass is vx = -3m/s , vy = 2m/s.

The total force is 54i +24j [N] (Not a given, calculated)

The question is:

At the instant the velocity is as above the string is cut. Where is the mass 4 seconds later? Ignore the effects of gravity and friction.

I really need some help with this one.. Thanks alot
 
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when cut the body is moving at -3m/s in the X
and 2m/s in the Y
will the direction or magnitude of any of these change after the string is cut?
what happens 4s later then? What is the displacement from the original position
 

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