Where does the normal line intersect the second time?

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Where does the normal line to the ellipse x2-xy+y2=3 at the point (-1,1) intersect the ellipse a second time?So I took the derivative of the equation to get:
y'=(2x-y)/(x-2y)
Then I put (-1,1) into the equation, to get a slope of 1.
So, for the normal line I got a slope of -1, which has the equation y=-x.

And that's as far as I got, I know the answer is suppose to be (1,-1).
 
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Nevermind, I figured it out.
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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