Where is the Mistake in My Extended Binomial Theorem Calculation?

talolard
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Homework Statement



Calculate \sqrt{1/20} using the extended binomial theormem. (a precision of k=4 is enough)


The Attempt at a Solution



\sqrt{1/20}= (1 + (-19/20) )^{1/2}= \sum( choose (1/2,k)*(-19/20)^k) = 1- 1/2*19/20-1/8*361/400+1/16*6589/8000 = 0.72... is wrong.

Homework Statement




Where is my mistake?
Thanks
Tal

Homework Equations





The Attempt at a Solution





 
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talolard said:

Homework Statement



Calculate \sqrt{1/20} using the extended binomial theormem. (a precision of k=4 is enough)


The Attempt at a Solution



\sqrt{1/20}= (1 + (-19/20) )^{1/2}= \sum( choose (1/2,k)*(-19/20)^k) = 1- 1/2*19/20-1/8*361/400+1/16*6589/8000 = 0.72... is wrong.

Homework Statement




Where is my mistake?
Thanks
Tal
You made a simple sign mistake somewhere, it seems.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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