Where to Place a Negative Charge for Zero Electric Field at the Origin?

AI Thread Summary
To achieve a net electric field of zero at the origin with a 40 µC charge located at x=4 cm, a negative 60 µC charge must be placed further to the right on the x-axis. The electric field due to each charge can be calculated using the formula E=Ke(q/r^2), but the net field requires considering the superposition of the fields from both charges. The negative charge's position must be determined so that its electric field counteracts the field from the positive charge. The discussion emphasizes that the placement of the negative charge is crucial for achieving equilibrium at the origin. Understanding the principle of superposition is key to solving this problem effectively.
Bearbull24.5
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Homework Statement


A 40 uC charge is placed on x-axis at x=4cm. Where should a negative 60 uC charge be placed to produce a net electric field of zero at the origin?


Homework Equations



Fe=Ke((q1*q2)/r^2)

The Attempt at a Solution



I tried rearranging this equation to solve for r
 
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Not quite. The idea is that there are two charges, the 40 uC charge is at a particular location, you need to figure out where another one must be placed to make the net field zero at the origin.

How do you find the electric field resulting from two charges?

Conceptually, around where would you guess the other charge should be placed?
 
Well I know it has to be located further to the right.

To find the Electric field from 2 charges... it wouldn't be as simple as using the equation E=Ke(q/r^2)?
 
Bearbull24.5 said:
Well I know it has to be located further to the right.
Totally.

Bearbull24.5 said:
To find the Electric field from 2 charges... it wouldn't be as simple as using the equation E=Ke(q/r^2)?
Not quite. That's the field due to a single point charge. Electric fields obey the principle of 'superposition,' however. To find the net field, you simply add the fields from each individual charge.
Formally:
<br /> E_{net} = \sum_{i=1}^{n} E_i<br />
for n charges
 
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