Which circuit can cause damage in the ampmeter or voltmeter?

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High current can damage an ampmeter due to its low resistance, making it unsuitable for direct connection across a voltage source. In contrast, voltmeters have high impedance, allowing them to measure voltage without significantly affecting the circuit. The discussion confirms that circuit configurations with high current can lead to ampmeter damage, while those with resistance can safely include voltmeters. Proper circuit design is crucial to prevent instrument damage. Understanding the characteristics of these meters is essential for safe and effective electrical measurements.
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Homework Statement


http://imgur.com/KvhqcEg

Which one of the circuits can cause damage in the ampmeter or voltmeter?

Homework Equations

The Attempt at a Solution


I am guessing a). If the current is high enough then the ampmeter is going to get damaged because the electrons are only going through the ampmeter. At first I though c) was wrong but it is right because the circuit has a resistance
 
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Yes. You have it right.
Amp meters offer little resistance, so you don't want to place them across a voltage.
On the other hand, volt meters present a very high impedance and so have little effect on electric currents.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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