Why Are Electric Dipole Selection Rules Confusing on the GRE?

yosofun
Messages
14
Reaction score
0
Hi, I have a question on selection rules for electric dipole transitions. It has to do with a GRE Physics exam question that's confusing a number of students at grephysics.net ... if any of the quantum guru's here would like to help, please check it out at http://grephysics.yosunism.com/disp.php?yload=prob&serial=1&prob=92

thank you.
 
Last edited by a moderator:
Physics news on Phys.org
The problem has to do with an excited atom that emits a photon. Spin doesn't contribute to the energy and so cannot provide a reason for a photon to be emitted. Intuitively, spin just doesn't get you going in the direction you need to go.

This wouldn't be the case if you were in a strong magnetic field, by the way.

Carl
 
what about delta j and delta n?

CarlB said:
The problem has to do with an excited atom that emits a photon. Spin doesn't contribute to the energy and so cannot provide a reason for a photon to be emitted. Intuitively, spin just doesn't get you going in the direction you need to go.
This wouldn't be the case if you were in a strong magnetic field, by the way.
Carl
 
Since j and n do contribute to the energy (unlike spin).

The reality is that there are always going to be some problems on the GRE that you're just not going to get right because the authors were too esoteric in their problem writing. There's probably some text out there that stresses this particular analysis.

The sad fact is that there are many analyses of basic physics in standard textbooks that are completely wrong. This doesn't stop them from asking you questions about it. But in this case, I think the answer is correct, but the problem is unnaturally difficult.

Carl
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top