Why can current be larger than placed charges in a wire?

Click For Summary
SUMMARY

The discussion clarifies that a current of 10 A can exist even when the total charge placed in a wire is significantly less than 1 C. This is due to the definition of current (I = nqvA), which measures the flow of charge per second. The volume of the wire allows for multiple smaller charges to flow simultaneously, reducing resistance and enabling higher current. The explanation emphasizes that charges can move more freely in larger volumes, minimizing collisions with static atoms in the wire.

PREREQUISITES
  • Understanding of electric current and charge flow
  • Familiarity with the equation I = nqvA
  • Knowledge of resistance and its impact on current
  • Basic concepts of charge density and volume in conductors
NEXT STEPS
  • Study the relationship between charge density and electric current
  • Explore the effects of wire diameter on resistance and current flow
  • Learn about the behavior of charges in conductive materials
  • Investigate the implications of Ohm's Law in practical applications
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in understanding the principles of electric current and charge dynamics in conductors.

plasma tail
Messages
1
Reaction score
0

Homework Statement



We have seen that a coulomb is an enormous amount of
charge; it is virtually impossible to place a charge of 1 C on an
object. Yet, a current of 10 A, is quite reasonable. Explain
this apparent discrepancy.

Homework Equations


I = nqvA

The Attempt at a Solution


i think it is because current is the amount of charge flow per second, and the amount of charge depends on the volume of the wire, hence current can be larger than the placed charges if volume of the wire is pretty big. is this a good answer? is there anything to add? thx
 
Physics news on Phys.org
I agree with: As you've already said, current is defined as the amount of charge flow per second, there could be many charges little charges but summing them up will result in 1 C, bigger volume mean less resistance so more current flow this can be explained (the bad way) because charges have more space to avoid hitting static atoms in the wire (also the reason you've mentionned) and I should mention all the charges flow on the surface,any way if we get into the math, ## I = \frac{\delta Q}{\delta t} ##, if we take for example ##\delta t = 0.01 s## mesure that ##\delta Q = 0.1C## passed, then we conclude that I = 10A, Cheers :D
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K