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Main Question or Discussion Point
Derived from this circuits 3 nodes are 3 equations using the NodeVoltageMethod
1. (V140)/12 + 5 + (V1V2)/20 + V1/25 = 0
2. (V2V1)/20 + (V2V3)/40  7.5  5 = 0
3. V3/40 + (V3V2)/40 + 7.5 = 0
The only pattern I can see here is that if it is at node 1 then it is always the node voltage belonging to node 1 (which is V1) minus something else. I know that "this" minus "this" gives you the voltage across the horizontal or sometimes vertical resistor but I don't know WHY. Why do you minus voltages from each other.
1. (V140)/12 + 5 + (V1V2)/20 + V1/25 = 0
2. (V2V1)/20 + (V2V3)/40  7.5  5 = 0
3. V3/40 + (V3V2)/40 + 7.5 = 0
The only pattern I can see here is that if it is at node 1 then it is always the node voltage belonging to node 1 (which is V1) minus something else. I know that "this" minus "this" gives you the voltage across the horizontal or sometimes vertical resistor but I don't know WHY. Why do you minus voltages from each other.
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