Why Does a Clock Appear Upside Down in a Mirror?

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When a clock is placed in front of a mirror, it reflects a mirror image, resulting in lateral inversion. This means that the positions of the hour and minute hands appear reversed, so 5:15 would look like 6:15 in the reflection. The discussion highlights confusion about the concept of lateral inversion, particularly regarding how it applies to clocks. Participants suggest conducting a simple experiment to observe the effect directly. Understanding lateral inversion is crucial for interpreting how mirrored images differ from their real counterparts.
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we keep a clock in front of the mirror,if lateral inversion occurs,what will happen?
 
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You mean other than the fact that you'll see a mirror image of the clock face?
 
when you keep letters in front of mirrors,lateral inversion occurs,
so this should happen for clocks as well.
 
here, i ask again, lateral inversion in clock kept in front of mirror?
 
Sorry, but I don't think anybody understands your question. If you're wondering whether you'll see a mirror image of a clock when you hold it in front of a mirror, the answer is yes, as I've already told you. The image of *anything* in a mirror is going to be mirrored (not surprisingly). If you are unsure, why don't you just perform an experiment to determine the answer to your question? Hold a clock up in front of a mirror and look at the image of the clock face.
 
ill be clear now..when i kept the clock in front of the mirror,5:15 appeared as 6:15 on the
left ,i am not totally convinced about the concept of lateral inversion,please explain it .
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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