Why Does an Electron Move from High to Low Electric Potential Energy?

AI Thread Summary
Electrons move from high to low electric potential energy due to the influence of electric fields created by charged plates. In a setup with a positively charged plate on the left and a negatively charged plate on the right, the electron, being negatively charged, is attracted to the positive plate. This movement decreases the electron's potential energy as it moves toward the region of lower potential. The forces acting on the electron from the electric field facilitate this transition, aligning with the principle that objects tend to move in a way that minimizes their potential energy. Understanding this concept is crucial for grasping the behavior of charged particles in electric fields.
stormagedon
Messages
3
Reaction score
0
1. Explain why the electron moves in the above way (from left to right between two parallel plates that is positively charged on the left, negatively charged on the right) in terms of electric potential energy



Homework Equations





3. I know the electron moves from left to right when released between two parallel plates with a small distance between them, but I can't explain it in terms of electric potential energy. Help!
 
Physics news on Phys.org
You mean why it moves from right to left? If the left is positively charged and the right is negatively charged, the (negatively charged) electron should move to the left.. Now as for how this is explained using potential energy.. Think, how do forces act on objects in relation to their potential energy? When gravity does work on you if you're at some height, does it increase or decrease your potential energy?
 
Forces act to decrease potential energy, right?
 
Yeah
 
So, electrons move in such a way as to decrease their potential energy?
 
Not exactly. The electrical forces from the plates (acting on the electron) act to decrease the electron's potential energy.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top