Why Does Cherenkov Radiation Form a Ring in a Concave Mirror Setup?

AI Thread Summary
Cherenkov radiation forms a ring in a concave mirror setup due to the geometry of light rays emitted by particles traveling faster than light in a medium. When the particle beam intersects the mirror, it creates two sets of rays—one tilted upwards and one downwards—that are focused to opposite points on the ring. The center of the ring aligns with the focal point of the mirror, and the radius can be determined based on the angles of the emitted Cherenkov waves. Understanding this setup requires visualizing the rays as parallel, simplifying the problem to a two-dimensional geometry. The discussion emphasizes the importance of considering all rays simultaneously to grasp the formation of the ring image.
ideasrule
Homework Helper
Messages
2,286
Reaction score
0

Homework Statement


See here: http://www.jyu.fi/kastdk/olympiads/ (year 2008, theoretical question set 2, question 2)

Let us consider a beam of particles moving with velocity v>c/n, such that the angle θ is small, along a straight line IS. The beam crosses a concave spherical mirror of focal length and center C, at point S. SC makes with SI a small angle α. The particle beam creates a ring image in the focal plane of the mirror. Explain why with the help of a sketch illustrating this fact. Give the position of the center O and the radius of the ring image.

Homework Equations


none


The Attempt at a Solution



I'm puzzling over the solutions to no avail. Why is the line from C to the center of the ring parallel to the particles' trajectory? Why is the line from C to the top of the ring, and the line from C to the bottom of the ring, parallel to the Cherenkov radiation's wavefront? I feel like I must be missing something obvious...
 
Last edited by a moderator:
Physics news on Phys.org
Does anybody have any idea? I have to figure this out pretty soon.
 
I could not find the question using your link. I cannot "see" the diagram from your description. It is too confusing without the diagram. Try to attach the diagram.
 
Stupid me; I forgot that "Copy Link Location" gives a direct URL. Here it is:

http://www.jyu.fi/kastdk/olympiads/2008/Theory_2_Problem.pdf

And here's the solution:

http://www.jyu.fi/kastdk/olympiads/2008/Theory_2_Solution.pdf
 
Last edited by a moderator:
Consider the situation in 2 dimensions, and consider all of the rays simultaneously. This is a geometry problem. Basically, it is as if the Cherenkov rays are coming in from infinite distance (because they are parallel), and so you just need to figure out where the mirror will focus them. You have two sets of rays to consider: the ones tilted upwards and the ones tilted downwards. The mirror will focus these two sets of rays to two separate points. Those two points are two opposite points on the ring.
 
Thanks! I was missing something very simple.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top