Why Does Increasing Velocity Decrease Pressure in Fluid Dynamics?

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Homework Help Overview

The discussion revolves around the relationship between velocity and pressure in fluid dynamics, particularly focusing on the concept of dynamic pressure as described by the equation 1/2(density)(velocity)^2. The original poster expresses confusion regarding the assertion that increasing velocity leads to a decrease in pressure.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of Bernoulli's equation and its components, questioning how static pressure, height changes, and dynamic pressure interact. There is also inquiry into whether the manipulated form of the equation refers to gauge pressure or change in gauge pressure.

Discussion Status

Participants are actively engaging with the concepts, with some providing insights into Bernoulli's equation and its application to fluid flow. Questions about the interpretation of terms and their meanings indicate a productive exploration of the topic.

Contextual Notes

The original poster's question suggests a potential misunderstanding of the relationship between dynamic pressure and overall pressure in fluid dynamics, highlighting the need for clarification on conservation laws in fluid flow.

Wombat11
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Homework Statement


This Is more of a conceptual question. If the equation for dynamic pressure is 1/2(density)(velocity)^2 then as velocity increases the pressure would also, but I was told that as velocity increases pressure decreases. If anyone could explain this to me that would be great.
 
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As an isolated term, your description of the relationship between dynamic pressure and velocity would be correct. But you will find that as applied to fluid flow there are conservation laws that tie it to other quantities.

Take a look at the Bernoulli equation.
 
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In Bernoulli's equation is it pretty much saying that (static/gauge pressure)+ (pressure due to change in height)+(dynamic pressure) is a constant? Also my teacher manipulated the equation so it was Gauge pressure=(d)(g)(change in height)+ 1/2(d)(change in velocity)^2. Would it be Gauge pressure or change in Gauge pressure? Thanks.
 
Wombat11 said:
In Bernoulli's equation is it pretty much saying that (static/gauge pressure)+ (pressure due to change in height)+(dynamic pressure) is a constant?
Along a streamline, yes.
Also my teacher manipulated the equation so it was Gauge pressure=(d)(g)(change in height)+ 1/2(d)(change in velocity)^2. Would it be Gauge pressure or change in Gauge pressure? Thanks.
I would think it would be change in gauge pressure, since the other terms are changes.
 
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