Why Does the Michelson-Morley Experiment Use T1-T2 Even After Rotation?

KIRIT PUROHIT
Messages
1
Reaction score
0
Pl. guide me for the doubts that i have in MME

In this experiment suppose L1 = L2 Then in this case will there be in any change in time difference T1-T2 calculated before and after rotation of the apparatus?

Another query is first we find T1-T2 now if first path is parallel to ether wind then T1>T2 & so T1-T2 is ok. But after rotating through 90 now T1 < T2 so why we do not write T2-T1?
 
Physics news on Phys.org
KIRIT PUROHIT said:
Pl. guide me for the doubts that i have in MME

In this experiment suppose L1 = L2 Then in this case will there be in any change in time difference T1-T2 calculated before and after rotation of the apparatus?
The hypothesis was that there should be a difference due to the speed of light being dependent upon the speed of the source relative to the medium (the ether). L1 and L2 were perpendicular to each other so as the Earth changed its position relative to the ether, there should be a difference between times taken for light to travel the two paths. As it turned out, there was a null result. No time difference was observed.

Another query is first we find T1-T2 now if first path is parallel to ether wind then T1>T2 & so T1-T2 is ok. But after rotating through 90 now T1 < T2 so why we do not write T2-T1?
But you would not know which direction the ether wind is travelling, so you would not know how either path is oriented to the ether wind. All you are interested in is measuring the magnitude of the time difference.

AM
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top