Why Does the Voltage Across a Capacitor Lag Behind the Input Voltage?

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The discussion centers on the phenomenon of voltage lag in capacitors, where the voltage across a capacitor (v0) lags the input voltage (vi) by 90 degrees. The explanation involves using a vector diagram to illustrate the phase relationships, with the current (I) as the reference phase. The voltage across the resistor is in phase with the current, while the capacitor voltage lags behind the current, leading to the conclusion that vi leads v0. The original poster seeks a more intuitive, non-calculus explanation of this concept, indicating a desire for clarity beyond mathematical proofs. Understanding this lag is crucial for grasping AC circuit behavior.
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Homework Statement



Can somebody explain why the voltage across the capacitor (v0) lags vi?


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The Attempt at a Solution


 

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I proved it with a vector diagram.
Let I be the reference phase ie. 0 degrees. Because the voltage across R is in phase with I it also has 0 phase.
The capacitor voltage V0 lags I by 90 degrees ie. -90
Vi=V0+Rvoltage.
This shows Vi vector after I (R voltage) but before V0.
Therefore Vi leads V0.

I still would appreciate a more intuitive explanation if somebody has one.
 
My old ARRL handbook explained this in a non-calculus way. I never bothered to try to understand it. It was obvious to me once I had diff eq's and transform techniques - meanwhile, I believe yours is the best intuitive explanation there is.
 
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