A ball falling from rest is located 45meters below its starting point 3.0s later. Assuming its acceleration is uniform, what is it's value? (air resistance is negligible) Relevant Equations - Equations for uniformly accelerated motion Δd=(v1 x Δt)+(a x Δt^2)/2 Attempt To solve: v1= 0 Δd=45m Δt=3.0s a=? a=(2Δd/Δt^2)-(2v1Δt/Δt^2) a= ((2 x 45)/9)-((0 x 3)/9) a=10m/s^2 If a ball is falling from rest(0 initial velocity) shouldn't it's acceleration be 9.8 seconds since gravity is constant? Is my equation wrong? Is my idea of time-acceleration misplaced?