Why Increasing Pully B's Diameter is Incorrect

AI Thread Summary
Increasing the diameter of pulley B does not decrease the force required to pull rope A because it increases the torque exerted by the mass on the center rotation point. If pulleys A and B were the same size, the forces on the ropes would equalize, rendering the system ineffective. To reduce the force on rope A while keeping pulley A the same size, pulley B must be decreased in diameter. This adjustment effectively increases the mechanical advantage by altering the torque dynamics in the system. Understanding these torque relationships is crucial for optimizing pulley systems.
syang9
Messages
61
Reaction score
0
http://dl.getdropbox.com/u/119319/pully-1.jpg

the book says the answer is C because 'increasing the diameter of the pully decreases the amount of force required to pull rope A'. I don't understand why increasing the diameter of pully B does not have the same effect (i.e., why D is incorrect.)
 
Last edited by a moderator:
Physics news on Phys.org
If pulley A and B were the same size the force on the ropes would be the same - the machine wouldn't be doing anything.
So making pulley B larger (ie closer in size to A ) does what to the force?

What would you have to do to pulley B to make the force on A smaller (if you left pulley A the same size)
 
okay, i understand now.. the pulley system works because it reduces the torque that the mass exerts on the center rotation point, and increases the torque that the user (pulling on rope a) exerts on the center rotation point. increasing pulley B diameter would increase the clockwise torque from the mass, so decreasing the size of pulley B (and keeping the size of A constant) would have the same effect as increasing the size of pulley A.
 
Exactly - you can also think of it as just a simple lever on a pivot in the centre.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top