Why is (B.y) for the y-component negative for sin30?

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The negative y-component for sin30 arises from the sign convention used in vector analysis, where "up" is considered positive and "down" negative. This means that sin30 can be interpreted as sin(-30) due to the angular displacement being in the opposite direction of the reference positive direction. When adding vectors, the y-components must reflect their respective directions, leading to opposite signs for components traveling in different directions from the x-axis. Consistency in applying the chosen sign convention is crucial for accurate calculations. Understanding this concept is essential for correctly interpreting vector components in physics problems.
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Hello, can someone please explain why (B.y) for the y-component is negative for the sin30. thanks .
question is below.

[PLAIN]http://img710.imageshack.us/img710/6150/resulant.jpg
 
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The y-component for the sin30 is because it's actually sin(-30): the angular displacement is in the opposite direction of the reference positive direction. Intuitively, this makes sense because when you add the vectors in component form you would get a vector whose y-component is greater than the y-component of the 8.00N @ 40degrees vector despite the fact that the vectors shown are traveling in opposite directions from the x-axis, that is, their y-components should have opposite signs.
 
Welcome to PF yardy_genius,

It's just a sign convention. By convention, you're taking "up" to be the positive y-direction and "down" to be the negative y-direction. You could just as easily adopt the opposite sign convention. All that matters is that you pick a convention and stick to it (i.e. use it consistently throughout the problem).
 
WJSwanson said:
The y-component for the sin30 is because it's actually sin(-30): the angular displacement is in the opposite direction of the reference positive direction. Intuitively, this makes sense because when you add the vectors in component form you would get a vector whose y-component is greater than the y-component of the 8.00N @ 40degrees vector despite the fact that the vectors shown are traveling in opposite directions from the x-axis, that is, their y-components should have opposite signs.

thanks alot
 
cepheid said:
Welcome to PF yardy_genius,

It's just a sign convention. By convention, you're taking "up" to be the positive y-direction and "down" to be the negative y-direction. You could just as easily adopt the opposite sign convention. All that matters is that you pick a convention and stick to it (i.e. use it consistently throughout the problem).

thanks , you guys really helped a lot
 
No problem; glad I could help. Cepheid's answer is also pretty important, by the way. He touched on a way more critical point than I did, which is that you can use almost any convention that's convenient, so long as you stick to it (and make sure to revert it to the original terms if necessary/requested).
 
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