Why is (B.y) for the y-component negative for sin30?

  • Thread starter Thread starter yardy_genius
  • Start date Start date
  • Tags Tags
    Resultant
Click For Summary

Homework Help Overview

The discussion revolves around understanding the sign of the y-component in vector analysis, specifically regarding the sine of an angle in relation to its direction. The original poster seeks clarification on why the y-component associated with sin(30) is considered negative in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the idea of sign conventions in vector components, questioning how the direction of angular displacement affects the sign of the sine function. There is also a discussion on the implications of adopting different conventions consistently throughout the problem.

Discussion Status

Participants have provided insights regarding the use of sign conventions and the rationale behind the negative sign for the y-component. There is recognition of the flexibility in choosing conventions, with multiple perspectives being explored without a definitive consensus.

Contextual Notes

There is an emphasis on the importance of consistency in applying sign conventions, as well as the potential for varying interpretations based on the chosen reference direction.

yardy_genius
Messages
13
Reaction score
0
Hello, can someone please explain why (B.y) for the y-component is negative for the sin30. thanks .
question is below.

[PLAIN]http://img710.imageshack.us/img710/6150/resulant.jpg
 
Last edited by a moderator:
Physics news on Phys.org
The y-component for the sin30 is because it's actually sin(-30): the angular displacement is in the opposite direction of the reference positive direction. Intuitively, this makes sense because when you add the vectors in component form you would get a vector whose y-component is greater than the y-component of the 8.00N @ 40degrees vector despite the fact that the vectors shown are traveling in opposite directions from the x-axis, that is, their y-components should have opposite signs.
 
Welcome to PF yardy_genius,

It's just a sign convention. By convention, you're taking "up" to be the positive y-direction and "down" to be the negative y-direction. You could just as easily adopt the opposite sign convention. All that matters is that you pick a convention and stick to it (i.e. use it consistently throughout the problem).
 
WJSwanson said:
The y-component for the sin30 is because it's actually sin(-30): the angular displacement is in the opposite direction of the reference positive direction. Intuitively, this makes sense because when you add the vectors in component form you would get a vector whose y-component is greater than the y-component of the 8.00N @ 40degrees vector despite the fact that the vectors shown are traveling in opposite directions from the x-axis, that is, their y-components should have opposite signs.

thanks a lot
 
cepheid said:
Welcome to PF yardy_genius,

It's just a sign convention. By convention, you're taking "up" to be the positive y-direction and "down" to be the negative y-direction. You could just as easily adopt the opposite sign convention. All that matters is that you pick a convention and stick to it (i.e. use it consistently throughout the problem).

thanks , you guys really helped a lot
 
No problem; glad I could help. Cepheid's answer is also pretty important, by the way. He touched on a way more critical point than I did, which is that you can use almost any convention that's convenient, so long as you stick to it (and make sure to revert it to the original terms if necessary/requested).
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 7 ·
Replies
7
Views
960
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
8K
Replies
13
Views
6K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
44
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
3
Views
6K