Why is Cv used instead of Cp for calculating the internal energy of a gas?

AI Thread Summary
The equation ΔU=mCvΔT represents the change in internal energy of a gas, where Cv is the specific heat at constant volume. Cv is used instead of Cp because, at constant volume, all energy input goes into increasing internal energy without performing external work. In contrast, at constant pressure, additional energy is required to account for the work done during expansion. This distinction is crucial for understanding energy changes in gases compared to liquids and solids, where expansion work is negligible. Thus, Cv is the appropriate choice for calculating internal energy changes in gases under constant volume conditions.
freshjunior
Messages
2
Reaction score
0
internal energy of a gas :(

Hi all! I have a problem with this equation ΔU=mCvΔT, where ΔU=change in internal energy, m=mass, Cv=specific heat of air/gas at constant volume,ΔT=change in temp. Although this expression is true for all processes which can be applied to a gas e.g polytropic, adiabatic, why is Cv used instead of Cp, which is specific heat of air/gas at constant pressure?:confused:
 
Engineering news on Phys.org


Hello freshjunior,
If the volume is kept constant the gas is unable to expand and none of the energy input is used to do external work all of it being used to raise the internal energy.If the pressure is constant you need the same energy input as above to raise the internal energy but extra input is needed to account for the work done.
Cv for gases is similar to the specific heat capacities of liquids and solids.The expansion of liquids and solids is so small that usually we assume that the work done during expansion is negligible.Gases can expand a lot but this expansion can be prevented by holding the gas in a container of fixed volume
 


oic. Thanks alot!
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
Back
Top