Why Is My Resistive Bridge Calculation Resulting in Different Voltages?

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The discussion centers on discrepancies in voltage calculations using a resistive bridge formula. The original formula applied was incorrect, leading to an unexpected result of 6V instead of the expected 1.5V. The correct equation for the output voltage should include the source voltage (V_s) and the proper resistor ratios. With a source voltage of 3V, achieving 6V in a passive circuit is impossible. Accurate application of the formula is crucial for correct voltage results in resistive bridge calculations.
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Homework Statement


I was trying to apply the formula of bridge


Homework Equations


V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})


The Attempt at a Solution


File is attached...Small numbers with resistor names are their values in ohms...
the answer I get is 6v...Here it is 1.5 v...
 

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Altairs said:

Homework Statement


I was trying to apply the formula of bridge

Homework Equations


V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})

The Attempt at a Solution


File is attached...Small numbers with resistor names are their values in ohms...
the answer I get is 6v...Here it is 1.5 v...

The equation should be:
V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s
WithV_s = 3V you could never have V_o = 6V with a totally passive circuit.
 

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