Why Is My Trebuchet's Initial Velocity So High?

AI Thread Summary
The discussion centers on calculating the initial velocity of a trebuchet using the equation mgh = 1/2 mv^2. The user reports an unusually high initial velocity of 110 m/s, which raises questions about their calculations. A response clarifies that the counterweight does not factor into the equation and provides a corrected formula for determining velocity. The correct approach involves using the height of the counterweight drop and gravitational acceleration to find the initial velocity. The conversation emphasizes the importance of proper application of physics principles in trebuchet design.
skylarr
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ok i had to build a trebuchet for high school and i can't seem to get a decent value for the initial velocity please help. i used a 60 pound counter weight (27.2 kg) a tennis ball to launch (.057 kg) and the counter weight drops about 1.3 m when it is launched i used the equation mgh = 1/2 mv ^2, but i got 110 m/s pleas help this is due tommmorow.

thanks
 
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Okay, I have no idea how you got 110. Anyway this model is very simplistic but still correct. Remember that the counterweight does not matter with your set of equations. Anyway the answer (according to your assumptions) should yield::smile:
therefore: 1.3*9.8=.5*v^2
therefore: v=SQRT(2*1.3*9.8)
 
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