Why is P/A equal to 83kPA at an eccentricity ratio of 1?

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At an eccentricity ratio of 1, the pressure-to-area ratio (P/A) is determined to be 83 kPa based on specific calculations. The vertical line is drawn at a value of kl/r equal to 104, which is provided in the first image referenced in the discussion. Participants emphasize the importance of understanding foundational concepts rather than attempting to learn extensive material in a short time. Clarification is sought on how the kl/r value is derived. The discussion highlights the necessity of grasping basic engineering principles to solve the problem effectively.
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Homework Statement


in this question , ( in second photo) i don't understand that why at eccentricity ratio = 1 , P/ A is 83kPA , why the vertical line is drawn at a point between 100 and 150 KL/r to find P/A ?

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The Attempt at a Solution


Is it wrong ? Or I left out something? [/B]
 

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The vertical line is drawn at the given kl/r of 104.
You are trying to cram 4 years of engineering into 4 weeks. It won't work. Focus on the basics please.
 
H
PhanthomJay said:
The vertical line is drawn at the given kl/r of 104.
You are trying to cram 4 years of engineering into 4 weeks. It won't work. Focus on the basics please.
How do we know that kl /r =104??
 
Given in first image
 
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