Why is the E field at 1m zero inside a shell with distributed charge?

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The electric field at a point inside a charged shell, such as at 1m in a shell with inner radius 2m and outer radius 3m, is zero because there is no charge enclosed within that radius. For a conducting shell, the electric field inside the cavity is always zero due to charge redistribution on the surface. If the shell is non-conducting, specific charge distributions must be present to maintain a zero electric field at that point. The discussion emphasizes the importance of charge distribution in determining the electric field behavior. Understanding these principles is crucial for analyzing electric fields in various materials.
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E Field in a shell(!)

I have a shell with an inner radius 2m and an outer radius 3m and a cahrge q on the shell(distributed) , why is the E field at 1m is zero(charge enclosed is zero inside the sphere i can obtain it is zero but why doesn't the E field lines go into the shell)(this can be either insulating or conducting) thank you...
 
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If the shell is made of a conducting material, then the field in the cavity and in the material would always be zero. But you have mentioned it may be non-conducting. Then some special charge distributions are necessary for the field to be zero at 1 m. You are missing some important info here.
 
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