Why is Voltage b/w 220 & 330 Olm Resistors 0V?

AI Thread Summary
The voltage between the 220-ohm and 330-ohm resistors is 0V because they are in series and no current flows through that section of the circuit, effectively creating an open circuit. The current in the circuit is calculated to be 9.8 mA, with voltage drops across the resistors being 2.157V for the 220-ohm resistor and 3.234V for the 330-ohm resistor. Since the measurement is taken across a conductor with negligible resistance, the voltage reads as 0V. This occurs because current prefers the path of least resistance, which bypasses the section between the two resistors. Understanding this concept is crucial for analyzing series circuits and voltage measurements.
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ok the question I have is why is the voltage between the 220 olm resistor and the 330 olm resistor 0 V.

All resistors in the image are in series so Is=I1=I2=I3

Is = 10/1020 (v/olm) = .0098 or 9.8 mA

V(subscript220)= 220*9.8 mA = 2.157 V (this is the voltage between the DC source and the 220 olm resistor)

V(subscript330) = 330 * 9.8 mA = 3.234 V (this is the voltage between the 330 olm and the 470 olm resistor)

V(subscript470) = 470 * 9.8 mA = 4.606 ( I have to add 3.234 to 4.606 to find the voltage between the DC source and 470 which is 7.84 V)

I am taking the ground up above the the 330 olm resistor.

Ok now I am not sure but I think the reason why the voltage across the 220 to the 330 olm resistor is zero is because I have to make a open circuit in that area which means that no current is actually passing through the wire since current takes the path of least resistence.
 

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ok the question I have is why is the voltage between the 220 olm resistor and the 330 olm resistor 0 V.
be careful how you word your question!
the answer to this question is that you are measuring the voltage on a 0 ohm conductor between r220 & r330
 

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