Why light exerts pressure on a metal surface

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SUMMARY

The discussion focuses on the electromagnetic force exerted on a metal surface by an incident monochromatic plane wave. By analyzing the electric field (E) and magnetic field (B) components, specifically using the equation F = q(E + v × B), it is established that mobile electrons experience a force due to the magnetic field when they are set in motion by the electric field. The net force on the metal surface is directed in the y-axis, resulting from the cross product of the velocity and magnetic field vectors. The logic presented in the analysis is confirmed as correct.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically Maxwell's equations.
  • Familiarity with the behavior of monochromatic plane waves.
  • Knowledge of vector calculus, particularly cross products.
  • Basic principles of electron mobility in conductive materials.
NEXT STEPS
  • Study the implications of F = q(E + v × B) in different electromagnetic contexts.
  • Explore the properties of monochromatic plane waves in various media.
  • Learn about the interaction of light with conductive materials, focusing on electron dynamics.
  • Investigate the applications of electromagnetic forces in technology, such as in photonic devices.
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and researchers interested in electromagnetic theory and its applications in materials science.

Eric Wright
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Homework Statement



By considering the E and B fields of an incident monochromatic plane wave on a metal surface, as well as the current density of mobile electrons, J and the resulting EM force F felt by them, show that there is a force on the metal due to the magnetic force on the mobile electrons.

Homework Equations



\vec F = q( \vec E + \vec v \times \vec B )

\vec E = E_0 e^{ky-wt} \hat k

\vec B = \frac{E_0}{c} e^{ky-wt} \hat i


The Attempt at a Solution



Let the surface be the zy plane. Then at the surface we have

\vec E = E_0 e^{-wt} \hat k
\vec B = \frac{E_0}{c} e^{-wt} \hat i

Consider a mobile electron on the surface. The E field will cause the electron to move in the -z direction. Then since the electron is now moving, the B field will exert a force in the
- \hat k \times \hat i = \hat j
direction. Applying this to all mobile electrons we get a net force in the y direction on the surface.

I just wanted to see if my logic here is correct.. Am I missing any important details?

Any reply would be great.. thanks!

Eric
 
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Eric Wright said:

Homework Statement



By considering the E and B fields of an incident monochromatic plane wave on a metal surface, as well as the current density of mobile electrons, J and the resulting EM force F felt by them, show that there is a force on the metal due to the magnetic force on the mobile electrons.

Homework Equations



\vec F = q( \vec E + \vec v \times \vec B )

\vec E = E_0 e^{ky-wt} \hat k

\vec B = \frac{E_0}{c} e^{ky-wt} \hat i


The Attempt at a Solution



Let the surface be the zy plane. Then at the surface we have

\vec E = E_0 e^{-wt} \hat k
\vec B = \frac{E_0}{c} e^{-wt} \hat i

Consider a mobile electron on the surface. The E field will cause the electron to move in the -z direction. Then since the electron is now moving, the B field will exert a force in the
- \hat k \times \hat i = \hat j
direction. Applying this to all mobile electrons we get a net force in the y direction on the surface.

I just wanted to see if my logic here is correct.. Am I missing any important details?

Any reply would be great.. thanks!

Eric

Looks right to me!
 

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